⚖️ Fundamental Limit Laws
Assume lim f(x) = L and lim g(x) = M exist as x→a:
lim [f(x) ± g(x)] = L ± M
lim [f(x) · g(x)] = L · M
lim [f(x) / g(x)] = L / M (M ≠ 0)
lim [c · f(x)] = c · L
lim [f(x)]ⁿ = Lⁿ
Example: lim (x² + 3x) = lim x² + lim 3x = 4 + 6 = 10 (x→2)
🔄 Continuity Conditions
A function f(x) is continuous at x = a if:
- f(a) is defined
- lim f(x) as x→a exists
- lim f(x) = f(a)
Discontinuity Types:
1. Removable (hole)
2. Jump
3. Infinite
If f and g are continuous at a, then f±g, f·g, f/g (g(a)≠0) are continuous
✨ Essential Trigonometric Limits
limₓ→₀ [sin(x)/x] = 1
limₓ→₀ [tan(x)/x] = 1
limₓ→₀ [(1 - cos(x))/x] = 0
limₓ→₀ [(1 - cos(x))/x²] = 1/2
Application: lim (sin 3x)/x = 3·lim (sin 3x)/(3x) = 3·1 = 3
Crucial for deriving trig derivatives
🏥 L'Hôpital's Rule
For indeterminate forms 0/0 or ∞/∞:
lim [f(x)/g(x)] = lim [f'(x)/g'(x)]
Requirements:
1. f(a) = g(a) = 0 or ±∞
2. f and g differentiable near a
3. g'(x) ≠ 0 near a (except possibly at a)
Example: lim (eˣ - 1)/x = lim eˣ/1 = 1 (x→0)
🥪 Squeeze Theorem
If g(x) ≤ f(x) ≤ h(x) near a and lim g(x) = lim h(x) = L:
Then lim f(x) = L
Classic: Show lim x² sin(1/x) = 0 using -x² ≤ x² sin(1/x) ≤ x²
Useful when direct substitution fails
∞ Limits at Infinity
limₓ→∞ [1/x] = 0
limₓ→∞ [aₙxⁿ + ...]/[bₘxᵐ + ...] =
{0 if n < m
aₙ/bₙ if n = m
±∞ if n > m}
limₓ→∞ eˣ = ∞
limₓ→-∞ eˣ = 0
ε-δ Definition
lim f(x) = L as x→a means:
∀ε > 0, ∃δ > 0 such that
0 < |x - a| < δ ⇒ |f(x) - L| < ε
Strategy:
1. Start with |f(x) - L| < ε
2. Work backwards to find δ
3. Verify your δ works
↔ One-Sided Limits
limₓ→a⁺ f(x) = L⁺ (right-hand limit)
limₓ→a⁻ f(x) = L⁻ (left-hand limit)
limₓ→a f(x) exists iff L⁺ = L⁻
Example:
f(x) = |x|/x
limₓ→0⁺ = 1, limₓ→0⁻ = -1
∴ limit does not exist
💪 Quick Practice Problems
Problem 1: lim (x² - 4)/(x - 2) as x→2
Answer: 4
Problem 2: lim (sin 5x)/(2x) as x→0
Answer: 5/2
Problem 3: lim (1 + 3/x)ˣ as x→∞
Answer: e³
Problem 4: Determine continuity of f(x) = {x² if x<1, 2x-1 if x≥1} at x=1
Answer: Continuous