DerivativeCalculus.com

Optimization & Related Rates Guide

Master real-world calculus applications with step-by-step strategies for optimization and related rates problems

📈 Optimization Problems: Finding Maximum/Minimum
1
Read & Understand
Carefully read the problem. Identify what needs to be maximized or minimized. Draw a diagram if possible.
Tip:
Underline key quantities and constraints.
2
Define Variables
Assign variables to all relevant quantities. Let x be the quantity you can control.
Tip:
Use descriptive variable names (length = L, width = W, etc.)
3
Write Equations
Write the primary equation (what to optimize) and constraint equations (given conditions).
Example:
Area = L × W (optimize), Perimeter = 2L + 2W = 100 (constraint)
4
Express in One Variable
Use constraint equations to express the primary equation in terms of a single variable.
From example:
If P = 2L + 2W = 100, then W = 50 - L
5
Find Derivative
Differentiate the primary equation with respect to your variable.
Remember:
You're finding where derivative = 0 (critical points)
6
Solve & Verify
Solve derivative = 0 for critical points. Check endpoints and use second derivative test if needed.
Test:
f''(x) > 0 → minimum, f''(x) < 0 → maximum
📐 Example: Maximum Area with Fixed Perimeter Optimization
A farmer has 100 meters of fencing to enclose a rectangular plot along a river (no fencing needed along river). What dimensions maximize the area?
Variables:
L = length (parallel to river)
W = width (perpendicular to river)
A = area to maximize
1
Primary Equation: Area = L × W
2
Constraint: Fencing used: L + 2W = 100 (only three sides needed)
3
Express in one variable: From constraint: L = 100 - 2W
Substitute: A(W) = (100 - 2W) × W = 100W - 2W²
4
Derivative: A'(W) = 100 - 4W
5
Find critical point: Set A'(W) = 0
100 - 4W = 0 → W = 25 meters
6
Find other dimension: L = 100 - 2(25) = 50 meters
7
Verify maximum: A''(W) = -4 < 0 → maximum
Maximum Area: 50m × 25m = 1250 m²
🎯 Problem-Solving Strategies & Tips
🧠 General Strategies for Word Problems
Draw Diagrams
Always sketch the situation. Label all known and unknown quantities.
Identify "What's Changing"
For related rates: What quantities vary with time? For optimization: What can we control?
Write Clear Notation
Use descriptive variable names. Always define your variables.
⚠️ Common Mistakes to Avoid
Substituting too early: Don't substitute known values before differentiating in related rates problems.
Forgetting units: Always include units in your final answer. Check that units make sense.
Ignoring endpoints: In optimization, check endpoints of the domain in addition to critical points.
Sign errors: Pay attention to whether rates are positive (increasing) or negative (decreasing).
Missing constraints: Read carefully for hidden constraints like physical limitations (can't have negative length, etc.).
Success Checklist
Optimization
✓ Diagram drawn
✓ Variables defined
✓ Primary equation identified
✓ Constraints identified
✓ Single-variable function created
✓ Derivative found
✓ Critical points found
✓ Endpoints checked
✓ Maximum/minimum verified
Related Rates
✓ Diagram drawn
✓ Variables defined with units
✓ Given and needed rates identified
✓ Relationship equation written
✓ Differentiated with respect to time
✓ Known values substituted
✓ Unknown rate solved
✓ Units included in answer
✓ Sign interpreted correctly
✏️ Practice Problems
Practice 1: Box Volume
From a 12×12 inch square piece of cardboard, squares are cut from each corner and sides folded up to make a box. What size squares maximize volume?
Hint: Volume = length × width × height. Let x be side length of cut squares.
Practice 2: Inflating Balloon
Air is pumped into a spherical balloon at 100 cm³/sec. How fast is radius increasing when radius is 10 cm?
Hint: Volume of sphere V = (4/3)πr³. You know dV/dt, need dr/dt.
Practice 3: Distance Between Cars
Car A travels north at 60 mph, Car B travels east at 80 mph. Both start from same intersection. How fast is distance between them changing after 2 hours?
Hint: Use Pythagorean theorem: D² = A² + B² where A and B are distances traveled.
Practice 4: Rectangle Area
Find dimensions of rectangle with area 100 m² that has minimum perimeter.
Hint: Area = L×W = 100. Perimeter P = 2L + 2W. Express P in terms of one variable using constraint.
📚 Need More Practice?

Visit our Calculators section for interactive problem solvers, or check our Resources page for more worksheets.