A 10-foot ladder leans against a wall. The bottom slides away from the wall at 2 ft/sec. How fast is the top sliding down when the bottom is 6 feet from the wall?
Variables:
x = distance from wall to ladder bottom
y = height of ladder on wall
dx/dt = 2 ft/sec (given)
dy/dt = ? (what we need)
L = 10 ft (constant ladder length)
1
Relationship: Pythagorean theorem
x² + y² = L² = 100
2
Differentiate with respect to t:
2x(dx/dt) + 2y(dy/dt) = 0
3
Simplify:
x(dx/dt) + y(dy/dt) = 0
4
Find y when x = 6:
6² + y² = 100 → y² = 64 → y = 8 ft
5
Substitute known values:
6(2) + 8(dy/dt) = 0
6
Solve for dy/dt:
12 + 8(dy/dt) = 0 → dy/dt = -12/8 = -1.5 ft/sec
Top is sliding down at 1.5 ft/sec (negative means decreasing)