How do I differentiate sin(x²) using the Chain Rule? Step-by-step help needed
Hi everyone! 👋
I am a second-year calculus student and I am struggling to understand how to apply the Chain Rule correctly. My professor gave us this problem and I cannot figure out the steps.
The function is:
$$f(x) = \sin(x^2)$$
I know the Chain Rule formula is:
$$\frac{d}{dx}[f(g(x))] = f'(g(x)) \cdot g'(x)$$
But I am confused about how to identify the outer function and the inner function here.
Here is what I tried so far:
I said the outer function is $f(u) = \sin(u)$ and the inner function is $g(x) = x^2$
Then I got:
$$f'(x) = \cos(x^2) \cdot 2x$$
Is this correct? And can someone explain WHY we multiply by $2x$ at the end? I understand the formula but not the intuition behind it.
Also, how would this change if the function was $\sin(x^3)$ or $\sin(2x+1)$?
Any help would be really appreciated. Thank you! 🙏
I am a second-year calculus student and I am struggling to understand how to apply the Chain Rule correctly. My professor gave us this problem and I cannot figure out the steps.
The function is:
$$f(x) = \sin(x^2)$$
I know the Chain Rule formula is:
$$\frac{d}{dx}[f(g(x))] = f'(g(x)) \cdot g'(x)$$
But I am confused about how to identify the outer function and the inner function here.
Here is what I tried so far:
I said the outer function is $f(u) = \sin(u)$ and the inner function is $g(x) = x^2$
Then I got:
$$f'(x) = \cos(x^2) \cdot 2x$$
Is this correct? And can someone explain WHY we multiply by $2x$ at the end? I understand the formula but not the intuition behind it.
Also, how would this change if the function was $\sin(x^3)$ or $\sin(2x+1)$?
Any help would be really appreciated. Thank you! 🙏