Implicit Differentiation: Complete Guide
Understand implicit differentiation technique with clear explanations and worked examples. Master this powerful method for finding derivatives when equations cannot be easily solved for y, essential for circles, ellipses, and complex relationships in calculus.
Many real-world relationships cannot be written as y = f(x). Circles, ellipses, and complex equations require implicit differentiation to find dy/dx. This technique is crucial for AP Calculus and advanced mathematics!
📑 Table of Contents
🎯 What is Implicit Differentiation?
Implicit differentiation is a technique for finding derivatives when the equation is not solved for y (i.e., not in the form y = f(x)).
Explicit vs. Implicit Functions
- Explicit: y = x² + 3x (y is isolated)
- Implicit: x² + y² = 25 (y is NOT isolated)
- Explicit: y = sin(x)/x
- Implicit: xy + y² = 10
When to Use Implicit Differentiation
Use this method when:
- The equation cannot be easily solved for y
- You're working with circles, ellipses, or other conic sections
- The equation has y terms mixed with x terms (like xy or x²y³)
- Solving for y would be complicated or messy
In implicit differentiation, we treat y as a function of x (y = y(x)) and apply the chain rule whenever we differentiate y terms.
📐 The Technique & Process
Core Principle
When differentiating terms with y, remember that y is a function of x, so we must use the chain rule and multiply by dy/dx.
d/dx[y²] = 2y · dy/dx
d/dx[y³] = 3y² · dy/dx
The 4-Step Process
Take d/dx of the entire equation
Whenever you differentiate a term with y, multiply by dy/dx
Move terms with dy/dx to the left, everything else to the right
Factor out dy/dx and divide to isolate it
Whenever you see a y term, remember: "Every y term gets multiplied by dy/dx when you differentiate!"
🌱 Basic Implicit Differentiation Examples
Let's start with fundamental examples to build your understanding.
Find dy/dx: x² + y² = 25
d/dx[x²] + d/dx[y²] = d/dx[25]
2x + 2y·(dy/dx) = 0
- 2y·(dy/dx) = -2x
- dy/dx = -2x/2y = -x/y
Find dy/dx: x³ + y³ = 6xy
3y²·(dy/dx) - 6x·(dy/dx) = 6y - 3x²
- (3y² - 6x)·(dy/dx) = 6y - 3x²
- dy/dx = (6y - 3x²)/(3y² - 6x)
- Simplified: dy/dx = (2y - x²)/(y² - 2x)
Find dy/dx: 2x + 3y = 12
Differentiate: 2 + 3·(dy/dx) = 0
Answer: dy/dx = -2/3
Find dy/dx: x²/4 + y²/9 = 1
Differentiate: (2x/4) + (2y/9)·(dy/dx) = 0
Answer: dy/dx = -9x/4y
⚡ Intermediate Implicit Differentiation Examples
Find dy/dx: xy + y² = 10
Use product rule on xy:
(1)·y + x·(dy/dx) + 2y·(dy/dx) = 0
Collect dy/dx terms:
x·(dy/dx) + 2y·(dy/dx) = -y
dy/dx = -y/(x + 2y)
Find dy/dx: sin(x + y) = x
Use chain rule on sin(x + y):
cos(x + y)·(1 + dy/dx) = 1
dy/dx = [1 - cos(x + y)]/cos(x + y)
Find dy/dx: x²y³ = 8
Use product rule: 2xy³ + x²·3y²·(dy/dx) = 0
dy/dx = -2xy³/3x²y² = -2y/3x
Find dy/dx: x³ + 2xy + y³ = 4
3x² + 2y + 2x·(dy/dx) + 3y²·(dy/dx) = 0
dy/dx = -(3x² + 2y)/(2x + 3y²)
🚀 Advanced Implicit Differentiation Applications
Find dy/dx: e^(xy) = x + y
Left side needs product rule inside exponential:
e^(xy)·(y + x·dy/dx) = 1 + dy/dx
dy/dx = (1 - y·e^(xy))/(x·e^(xy) - 1)
Find dy/dx: ln(xy) = x - y
Apply chain rule: (1/xy)·(y + x·dy/dx) = 1 - dy/dx
Multiply by xy: y + x·dy/dx = xy - xy·dy/dx
dy/dx = (xy - y)/(x + xy)
Find d²y/dx²: x² + y² = 25
First, find dy/dx = -x/y
Then differentiate dy/dx using quotient rule:
d²y/dx² = -[y - x·(dy/dx)]/y² = -25/y³
⚠️ Common Mistakes to Avoid
Wrong: d/dx[y²] = 2y
Right: d/dx[y²] = 2y·(dy/dx)
Why: y is a function of x, so you MUST use chain rule!
Wrong: d/dx[xy] = y
Right: d/dx[xy] = y + x·(dy/dx)
Why: Use product rule for x times y!
Don't stop after differentiating! You must solve for dy/dx by collecting all dy/dx terms and factoring them out.
Remember: y depends on x! Unlike constants, y changes as x changes, so it needs dy/dx when differentiated.
Practice Problems
- x² + y² = 16 → Find dy/dx
- 3x + 4y = 24 → Find dy/dx
- x² - y² = 9 → Find dy/dx
- xy = 10 → Find dy/dx
- dy/dx = -x/y
- dy/dx = -3/4
- dy/dx = x/y
- dy/dx = -y/x
- x²y + xy² = 6 → Find dy/dx
- sin(y) = x → Find dy/dx
- x³ + y³ = 3xy → Find dy/dx
- e^y = x² → Find dy/dx
- dy/dx = -(2xy + y²)/(x² + 2xy)
- dy/dx = 1/cos(y)
- dy/dx = (y - x²)/(y² - x)
- dy/dx = 2x/e^y
- cos(xy) = x → Find dy/dx
- tan(x + y) = x → Find dy/dx
- x² + y² = 25 → Find d²y/dx²
- x·e^y + y·e^x = 1 → Find dy/dx
- dy/dx = [1 + y·sin(xy)]/[x·sin(xy)]
- dy/dx = [1 - sec²(x + y)]/sec²(x + y)
- d²y/dx² = -25/y³
- dy/dx = -(e^y + y·e^x)/(x·e^y + e^x)
🚀 Practice with Our Calculator
Verify your implicit differentiation solutions with step-by-step explanations!
Try Implicit Differentiation Calculator →📚 Key Takeaways
- Key Rule: Every y term gets multiplied by dy/dx
- Process: Differentiate → Collect dy/dx → Solve
- Remember: Use product rule for xy terms and chain rule for y terms
- Practice: Work through circles, ellipses, and complex equations
Strengthen your calculus foundation with these related guides:
- Chain Rule Guide - Essential for understanding implicit differentiation
- Product Rule Tutorial - Needed for xy terms
- All Derivative Rules - Complete reference