Derivative Troubleshooting Guide

Diagnose and fix common derivative calculation errors with step-by-step solutions

🔧 Fix Common Errors 🎯 Step-by-Step Solutions 📊 Visual Diagnostics ⚡ Quick Fixes

🔍 Error Diagnostic Tool

What's Your Error?

⛓️ Chain Rule Troubleshooting

Error: Forgetting to Multiply by Inner Derivative

Common

❌ Incorrect Solution

Function: f(x) = sin(x²)

Student's answer: f'(x) = cos(x²)

✅ Correct Solution

f(x) = sin(x²)

f'(x) = cos(x²) · 2x

f'(x) = 2x cos(x²)

🔬 Diagnosis

The student correctly identified the outer function (sin) but forgot to multiply by the derivative of the inner function (x²).

💡 Solution Steps

  1. Identify inner function: g(x) = x²
  2. Identify outer function: f(u) = sin(u)
  3. Apply chain rule: f'(x) = f'(g(x)) · g'(x)
  4. Calculate: f'(x) = cos(x²) · 2x
  5. Simplify: f'(x) = 2x cos(x²)

🛡️ Prevention Tips

  • Always write out both functions separately
  • Use parentheses to clearly show composition
  • Check: "Did I multiply by the derivative of the inside?"

Error: Misidentifying Inner and Outer Functions

Intermediate

❌ Incorrect Solution

Function: f(x) = (sin x)²

Student's answer: f'(x) = 2x sin(x)

✅ Correct Solution

f(x) = (sin x)² = sin²(x)

Let u = sin x, then f(u) = u²

f'(x) = 2u · u' = 2 sin x · cos x

f'(x) = 2 sin x cos x = sin(2x)

💡 Solution Steps

  1. Rewrite: f(x) = [sin(x)]²
  2. Inner function: g(x) = sin(x)
  3. Outer function: f(u) = u²
  4. g'(x) = cos(x)
  5. f'(x) = 2·sin(x)·cos(x)
  6. Use identity: 2 sin x cos x = sin(2x)

✖️ Product Rule Troubleshooting

Error: Adding Instead of Following Product Rule

Common

❌ Incorrect Solution

Function: f(x) = x · sin(x)

Student's answer: f'(x) = 1 + cos(x)

✅ Correct Solution

Let u = x, v = sin(x)

u' = 1, v' = cos(x)

f'(x) = u'v + uv'

f'(x) = 1·sin(x) + x·cos(x)

f'(x) = sin(x) + x cos(x)

🔬 Diagnosis

The student added the derivatives instead of using the product rule formula.

🎵 Helpful Mnemonic

"Derivative of First times Second,
Plus First times Derivative of Second"

➗ Quotient Rule Troubleshooting

Error: Getting Signs Wrong in Numerator

Very Common

❌ Incorrect Solution

Function: f(x) = (x² + 1)/(x - 1)

Student's answer: f'(x) = [2x·(x-1) + (x²+1)·1] / (x-1)²

✅ Correct Solution

Let u = x² + 1, v = x - 1

u' = 2x, v' = 1

f'(x) = (u'v - uv') / v²

f'(x) = [2x·(x-1) - (x²+1)·1] / (x-1)²

f'(x) = (2x² - 2x - x² - 1) / (x-1)²

f'(x) = (x² - 2x - 1) / (x-1)²

🎵 Helpful Mnemonic

"Low D-High minus High D-Low,
Over the Square of What's Below"

📝 Sign & Parentheses Troubleshooting

Error: Distributing Negative Signs Incorrectly

Common

❌ Incorrect Solution

Function: f(x) = 3x² - 4x + 5

Student's answer: f'(x) = 6x - 4 + 0 = 6x - 4

But then: f''(x) = 6 - 0 = 6

Error: Forgot negative sign in second derivative

✅ Correct Solution

f(x) = 3x² - 4x + 5

f'(x) = 6x - 4

f''(x) = 6

Note: -4 differentiates to 0, not -0

💡 Important Tip

When differentiating polynomials, handle each term separately. Constants become 0, and coefficients carry through with proper signs.

Error: Missing Parentheses in Chain Rule

Common

❌ Incorrect Solution

Function: f(x) = e^(2x + 3)

Student's answer: f'(x) = e^2x + 3 · 2

✅ Correct Solution

f(x) = e^(2x + 3)

Let u = 2x + 3

f'(x) = e^(2x + 3) · 2

f'(x) = 2e^(2x + 3)

💡 Parentheses Rule

Always use parentheses when the exponent contains more than one term. e^(2x+3) is different from e^2x + 3.

🎯 Interactive Error Finder

Find Errors in These Solutions

Exercise 1: Find the error

Function: f(x) = (x² + 1)³

Given solution: f'(x) = 3(x² + 1)² · 2x = 6x(x² + 1)²

Is this correct?

Exercise 2: Find the error

Function: f(x) = x · e^x

Given solution: f'(x) = 1 · e^x = e^x

What's wrong?

✅ Error Prevention Checklist

Before Starting

  • Identify function type (polynomial, trigonometric, etc.)
  • Check for composition (chain rule needed?)
  • Check for products/quotients

During Calculation

  • Write out each step clearly
  • Use parentheses generously
  • Check signs at each step

After Calculation

  • Verify with calculator tool
  • Check domain restrictions
  • Simplify final answer

📚 Additional Help Resources